Selasa, 11 Oktober 2011

EXPONENTIAL AND LOGARITHMIC FUNCTIONS (Part-4)

─►Logarithmic and Exponential Equations

 Exponential Equations

An exponential equation is an equation containing a variable in an exponent. The following property of logarithms can be used to solve many exponential equations:
Property of Logarithms, Part 2
If x, y, and a are positive numbers, a ¹ 1, then
1. If x = y, then
2. If , then x = y.
Exponential equations can be solved by isolating the exponential expression; using Property of Logarithms, Part 2 to take the log of both sides; simplifying; and then solving for the variable.


Example. Solve:
Solution.
 
Use Property of Logarithms, part 2, to take the log of both sides
x log 10 = log 5.71 Property of Logarithms:
x × 1 = log 5.71 Property of Logarithms:
x » 0.7566  


Example. Solve:
Solution.
 
Divide both sides by 7
Use Property of Logarithms, Part 2, to take the log of both sides
Property of Logarithms:
ln e = 1
Divide both sides by 3
x » 1.266  



Logarithmic Equations

Logarithmic equations contain logarithmic expressions and constants. When one side of the equation contains a single logarithm and the other side contains a constant, the equation can be solved by rewriting the equation as an equivalent exponential equation using the definition of logarithm. For example,

 
Definition of logarithm
16 = x + 3 Simplify
13 = x Solve for x
All solutions of logarithmic equations must be checked, because negative numbers do not have logarithms:

Check:  
Substitute the solution, 13, in place of x
Simplify
2 = 2 because
If one side of a logarithmic equation contains more than one logarithm, use properties of logarithms to condense them into a single logarithm. For example:

 
Property of Logarithms:
Definition of Logarithm
8 = x- 7x Simplify
0 = x- 7x – 8 Write quadratic equation in standard form
0 = (x – 8)(x + 1) Solve by factoring
x – 8 = 0 or x + 1 = 0
x = 8 or x = -1
 
Check:

   
Substitute the solution 8 for x Substitute the solution –1 for x
Subtract Subtract
3 + 0 = 3 because ; because   The number -1 does not check, since negative numbers do not have logarithms
3 = 3      
The solution set is {8}.

In the next example, every term contains a logarithmic expression. We will solve this equation by using logarithmic properties to rewrite each side as a single logarithm. We then use Property of Logarithms, Part 2, and set the quantities equal to each other.
Example. Solve: log (2x – 1) = log (4x – 3) – log x
Solution.

log (2x – 1) = log (4x – 3) – log x  
Property of Logarithms:
Property of Logarithms, Part 2
x(2x – 1) = 4x – 3 Multiply both sides by x
2x - x = 4x – 3 Distributive Property
2x - 5x + 3 = 0 Write the quadratic equation in standard form
(2x – 3)(x – 1) = 0 Solve by factoring
2x - 3 = 0 or x – 1 = 0  
2x = 3 or x = 1
x =
 
Check: x =

log (2x – 1) = log (4x – 3) – log x  
Substitute the solution for x
log 2 = log 3 – log 1.5 Simplify
log 2 = log Property of Logarithms:
log 2 = log 2  
Check: x = 1

log (2x – 1) = log (4x – 3) – log x  
log (2(1) – 1) = log (4(1) – 3) – log 1 Substitute the solution 1 in place of x
log 1 = log 1 – log 1  
0 = 0  
Both solutions check, so the solution set is .